# 4×2 9y2 16z2 12xy 24yz 16xz Factorise

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Ex 2 4 5 I Factorise 4x 2 9y 2 16z 2 12xy 24yz 16xz

Ex 2 4 5 I Factorise 4x 2 9y 2 16z 2 12xy 24yz 16xz Solution verified by toppr we know that, the algebraic identity: (a2 b2 c2 2ab 2bc 2ca) =(a b c)2 (i) 4x2 9y2 16z2 12xy−24yz−16xz here, yz and xz terms are negative. i.e., common variable z is in negative form. = (2x)2 (3y)2 (−4z)2 2(2x)(3y) 2(3y)(−4z) 2(−4z)(2x) = (2x 3y−4z)2 [∵ (a2 b2 c2 2ab 2bc 2ca)= (a b c)2] = (2x 3y−4z)(2x 3y−4z). Transcript. ex 2.4, 5 factorise: 4x2 9y2 16z2 12xy – 24yz – 16xz 4x2 9y2 16z2 12xy – 24yz – 16xz = 22 x2 32 y2 42 z2 12xy – 24yz – 16xz.

Factorise The Following 4x2 9y2 16z2 12xy 24yz 16xz Brainly In

Factorise The Following 4x2 9y2 16z2 12xy 24yz 16xz Brainly In Factrorise 4x2 9y2 16z2 12xy−24xyz−16zx q. let p (x)=4x2 9y2 16z2 12xy 24yz 16xz factorize p (x) for x=1,y=1,z=1. q. state true or false. 4x2 9y2 16z2 12xy−24yz−16xz = (2x 3y−4z)(2x 3y−4z) view more related videos algebraic identities mathematics watch in app standard ix mathematics join byju's learning program. 1 1 16 0 √2xy 4√2yz − 8xz 2 x 2 y 2 8 z 2 2 2 x y 4 2 y z 8 x z. asked jan 17, 2020 in mathematics by priyanshusingh (24.9k points) class 10. Factorise:(i) 4x2 9y2 16z2 12xy – 24yz – 16xz(ii) 2x2 y2 8z2 – 2 2 xy 4 2 yz – factorise 4x2 9y2 16z2 12xy 24yz 16zx | class 9 maths chapter 25 . Solution: we will be using the algebraic identity (a b c)² = a² b² c² 2ab 2bc 2ca to solve the following. i) 4x² 9y² 16z² 12xy 24yz 16xz this can be re written as: (2x)² (3y)² ( 4z)² 2 (2x) (3y) 2 (3y) ( 4z) 2 ( 4z) (2x) this is of the form a² b² c² 2ab 2bc 2ca = (a b c)² here a = 2x, b = 3y, c = 4z.

Factorise 4x 2 9y 2 16z 2 12xy 24yz 16xz Class 11 Math Doubtnut

Factorise 4x 2 9y 2 16z 2 12xy 24yz 16xz Class 11 Math Doubtnut Factorise:(i) 4x2 9y2 16z2 12xy – 24yz – 16xz(ii) 2x2 y2 8z2 – 2 2 xy 4 2 yz – factorise 4x2 9y2 16z2 12xy 24yz 16zx | class 9 maths chapter 25 . Solution: we will be using the algebraic identity (a b c)² = a² b² c² 2ab 2bc 2ca to solve the following. i) 4x² 9y² 16z² 12xy 24yz 16xz this can be re written as: (2x)² (3y)² ( 4z)² 2 (2x) (3y) 2 (3y) ( 4z) 2 ( 4z) (2x) this is of the form a² b² c² 2ab 2bc 2ca = (a b c)² here a = 2x, b = 3y, c = 4z. Solution verified by toppr we know that, a 2 b 2 c 2 2ab 2bc 2ac=(a b c) 2 now, 4x 2 9y 2 16z 2 12xy−24yz−16xz =(−2x) 2 (−3y) 2 (4z) 2 2(−2x)(−3y) 2(−3y)(4z) 2(−2x)(4z) =(−2x−3y 4z) 2 =(−2x−3y 4z)(−2x−3y 4z) was this answer helpful? 0 0 similar questions if (x y z)=9 and (xy yz zx)=9, then find the value of (x 2 y 2 z 2). easy view solution >. Factorise: 4x^2 9y^2 16z^2 12xy 24yz 16xzfactorize: 4x2 9y2 16z2 12xy 24yz 16xz.

Q4 Q5 Ex2 5 Ncert Expand 1 4a 1 2b 1 2 Factorise 4x2 9y2

Q4 Q5 Ex2 5 Ncert Expand 1 4a 1 2b 1 2 Factorise 4x2 9y2 Solution verified by toppr we know that, a 2 b 2 c 2 2ab 2bc 2ac=(a b c) 2 now, 4x 2 9y 2 16z 2 12xy−24yz−16xz =(−2x) 2 (−3y) 2 (4z) 2 2(−2x)(−3y) 2(−3y)(4z) 2(−2x)(4z) =(−2x−3y 4z) 2 =(−2x−3y 4z)(−2x−3y 4z) was this answer helpful? 0 0 similar questions if (x y z)=9 and (xy yz zx)=9, then find the value of (x 2 y 2 z 2). easy view solution >. Factorise: 4x^2 9y^2 16z^2 12xy 24yz 16xzfactorize: 4x2 9y2 16z2 12xy 24yz 16xz.

# Factorize 4x2 9y2 16z2 12xy 24yz 16xz, Ex 2.5 Q5 Math Class 9 Ncert Solutions (math Class Channel)

Factorize 4x2 9y2 16z2 12xy 24yz 16xz, Ex 2.5 Q5 Math Class 9 Ncert Solutions (math Class Channel)

factorise: 4x^2 9y^2 16z^2 12xy 24yz 16xz factorize: 4x2 9y2 16z2 12xy 24yz 16xz. class 9th maths exercise 2.5, q. no 5 chapter 2, polynomials factorise: (i) 4x2 9y2 16z2 12xy – 24yz – 16xz (ii) 2x2 y2 factorise 4x2 9y2 16z2 12xy 24yz 16zx | class 9 maths chapter 2 5. factorise: (i) 4x2 9y2 16z2 12xy – 24yz – 16xz (ii) factorise 4x^2 9y^2 16z^2 12xy 24yz 16xz | factorise 2x2 y2 8z2 2√2xy 4√2yz 8xz | class 9th | number system | class 9th class 9th || cbse || ncert book || polynomials || question 5(i) factorise: 4x^2 9y^2 16z^2 12xy−24yz 4x^2 9y^2 16z^2 12xy 24yz 16xz. hello students, in this video, i have explained how to factorise the expressions by using appropriate identities. we hope after निम्नलिखित प्रत्येक व्यंजक के गुणनखण्ड़ कीजिए: ex 2.5 q5. factorise:(i) 4x² 9y² 16z² 12xy – 24yz – 16xz for short notes, revision notes and ncert solution. visit us at factorise : (i) 4x^(2) 9y^(2) 16z^(2) 12xy 24yz 16xz (ii) 2x^(2) y^(2) 8z^(2) 2sqrt(2)xy 4sqrt(2)yz 8xz class: 9 subject: maths

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